Can anyone explain this “magic trick”/illusion? I see that somethings strange but i can’t figure it out.
March 17, 2009 · Filed Under Mathematics
jassie192000 asked:
Choose any two digit number, add together both digits and then subtract the total from your original number. *When you have the final number look it up on the chart and find the relevant symbol. Concentrate on the symbol and when you have it clearly in your mind click on the crystal ball and it will show you the symbol you are thinking of…
www.subliminalmessages.com/lifeinsurance32.htm
href=’http://www.collectiblewebkinz.com’>collectible webkinz
Choose any two digit number, add together both digits and then subtract the total from your original number. *When you have the final number look it up on the chart and find the relevant symbol. Concentrate on the symbol and when you have it clearly in your mind click on the crystal ball and it will show you the symbol you are thinking of…
www.subliminalmessages.com/lifeinsurance32.htm
href=’http://www.collectiblewebkinz.com’>collectible webkinz
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4 Responses to “Can anyone explain this “magic trick”/illusion? I see that somethings strange but i can’t figure it out.”
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9
notice that 00, 9, 18, 27, 36, 45, 54, 63, 72, 81, 90, 99
are all the multiples of “9″ …
99, 90 and 00 will never be the result of subtracting the sum of the digits of a two-digit number from that 2-digit number.
9, 18, 27, 36, 45, 54, 63, 72, 81 all have identical symbols associated with them …
“In modulus 9, the sum of the digits of a integer *equal* that number [mod 9] ”
sketch of a proof:
8437 = 8*10^3 + 4*10^2 + 3*10^1 +7*10^0
10 = 9+1
8437 = 8*(9+1)^3 + 4*(9+1)^2 + 3*(9+1)^1 +7*(9+1)^0
as example:
(9+1)^3 =C(3,0) (9^3)(*1^0) + C(3,1) (9^2)(*1^1)
+ C(3,2) (9^1)(*1^2) + C(3,3) (9^0)(*1^3
[where C(n,k) = n!/((k!)*(n-k)!)
sheesh, gettting very complicated iin notastion here …
main point is that the “remainder” of
8*(9+1)^3 when divided by 9 is equal to “8″ since all the other terms in the expansion are divisible by 9, thus having “0″ remainder .. and the “last term” of 1 * 8 = 8.
sooooooooooo ….
doing allthe “adding digits and subrtaacting the sum will ALWAYS yield a multple of “9″.
eg 83 - (8 + 3) = 83 - 11 = 72 ..and 72 = 9*8 .. and has
the same symbol as 9, 18, 27 … 81
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ha, check out the symbols for 9, 18, 27, 36, 45 and multiples of 9. they are same… co-incidence…… i don’t think so. guess you got the answer for the illusion. if not let me know
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it’s just math.
any 2 digit number that you choose, you will arrive at an answer divisible by 9.
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What is happening here is the following. You pick a two digit number. Let x be the first digit and y the second.
THen the number is 10 * x + y. Now you subtract x and y from that and you will get 10 * x + y - y - x = 9x.
So, the answer will be a multiple of 9 no matter what. If you look at the list of answers, every mulitple of 9 has the same value and the “crystal ball” gives the symbol associated with 9, 18, 27 . . .